Adriver of a car enters a new 110 km/h speed zone on the highway. the driver immediately begins to accelerate and reaches 110 km/h after driving 500 m. if the original speed was 80 km/h, what was the driver’s acceleration?

The formula for calculating acceleration can be derived from:

v^2 = v0^2 + 2 a d

where a is acceleration, v is final velocity, v0 is initial velocity and d is distance = 0.5 km

Rewriting in terms of a:

a = (v^2 – v0^2) / 2 d

a = (110^2 – 80^2) / (2 * 0.5)

a = 5,700 km/h^2 = 0.44 m/s^2

talk back to him about the sport and show him your expertise or leave the room

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle