An exoplanet has four times the mass and one-fourth the radius of the earth. find the acceleration due to gravity on its surface, in terms of g, the acceleration of gravity at earth's surface.

The formula for acceleration due to gravity can be calculated using the formula:

g= G m / r^2

where g is gravity, G is gravitational constant, m is mass, r is radius

So we can see that if we increase m by 4, so g also increase by 4. But if the radius is decreased to ¼, therefore the gravity will be divided by (1/4)^2. So:

4 / (1/4)^2 = 64

So the gravity on the surface will be:

64 g

(64 times that of Earth’s gravity)

15.3 cos 65 degrees trig

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer