The edge of a flying disc with a radius of 0.13 m spins with a tangential speed of 3.3 m/s. the centripetal acceleration of the edge of the disc m/s2. a. 0.0051 b. 0.43 c. 25 d. 84

The correct answer is

D. 84

Explanation:

The centripetal acceleration of the edge of the disc is given by:

where

v=3.3 m/s is the tangential speed at the edge of the disc

r=0.13 m is the radius of the disc

Therefore, substituting the numbers into the equation, we find the centripetal acceleration:

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