Atruck covers 40.0 m in 8.50 s while smoothly slowing down to a final speed of 2.80 m/s. (a) find its original speed. (b) find its acceleration.

For a: The original speed of the truck is 4.76 m/s

For b: The acceleration of the truck is

Explanation:

Speed is defined as the rate at which an object moves with respect to time.

To calculate the time taken for the given speed, we use the equation:

where,

s = speed of the truck

d = distance traveled = 40.0 m

t = time taken by truck = 8.50 s

Putting values in above equation, we get:

Hence, the original speed of the truck is 4.76 m/s

Acceleration is defined as the rate of change of velocity with respect to time.

Mathematically,

where,

v = final velocity  of the truck = 2.80 m/s

u = initial velocity  of the truck = 4.76 m/s

t = time taken  = 8.50 s

Putting values in above equation, we get:

Negative sign represents slowing down or deceleration.

Hence, the acceleration of the truck is

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