The electric field between two parallel plates has a magnitude of 875 n/c. the positive plate is 0.002 m away from the negative plate. what is the electric potential difference between the plates? 2.3 × 10-6 v 1.8 × 100 v 8.8 × 102 v 4.4 × 104 v

Answer : Electric potential,

Explanation :

It is given that,

Magnitude of electric field,

Distance between two plates,

The relation between the electric field and the electric potential is given by :

or

So, the magnitude of electric potential is given by option (2).

Hence, this is the required solution.                                                                                                

explanation:

could i give you a exaplo that could you?

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2