An object is dropped from a height of 75.0 m above ground level. (a) determine the distance traveled during the first second.

The relevant formula we can use in this case would be:

h = v0 t + 0.5 g t^2

where,

h = height or distance travelled

v0 = initial velocity = 0 since it was dropped

t = time = 1 seconds

g = 9.8 m/s^2

So calculating for height h:

h = 0 + 0.5 * 9.8 m/s^2 * (1 s)^2

h = 4.9 meters

an energy transformation flow diagram is shown

where is it ?

battery with hi vtge high val resist in series