Aflea jumps by exerting a force of 1.27 10-5 n straight down on the ground. a breeze blowing on the flea parallel to the ground exerts a force of 1.20 10-6 n on the flea. find the direction and magnitude of the acceleration of the flea if its mass is 6.0 10-7 kg. (let us assume that fwind points to the right. we will consider this to be the +x direction and vertical to be the +y direction.)

Since force is a vector quantity, we can find the net force by determining the resultant force. The equation is written below:

F = √(Fx²)+(Fy)²
where 
Fx is the force parallel to the ground
Fy is the downward force
F = √(1.2×10⁻⁶ N)²+(1.27×10⁻⁵ N)²
F = 1.2788×10⁻⁵ N

Then, we apply Newton's second law of motion.
F = ma
a = F/m = 1.2788×10⁻⁵ N/(6×10⁻⁷ kg)
a = 21.31 m/s²

The magnitude of the acceleration is 21.31 m/s². The direction is shown in the picture, which is headed towards southeast.

The answer will be d. reflects light because it cant be all the others because light cant be other things other than light