Two thin rods of length L are rotating with the same angular speed, W (in rad/s) about axes that pass perpendicularly through one end. Rod A is massless but has particle of mass 0.63 kg attached to its free end. Rod B has mass of 0.63 kg, which is distributed uniformly along its length. The length of each rod is 0.82 m, and the angular speed is 4.2 rad/s. Find the kinetic energies of rod A with its attached particle and of rod B.

Rod A: 3.74 J

Rod B: 3.74 J

STEP-BY-STEP EXPLANATION:

Rod A:

Length of the Rod = l = 0.82 m

Mass of particle attached = m = 0.63 kg

Moment of inertia of the system about given axis:

Angular speed of the rod = 4.2 rad/s

Kinetic energy of the rod is:

Rod B:

Length of the Rod = l = 0.82 m

Mass of particle attached = m = 0.63 kg

Moment of inertia of the system about given axis:

Angular speed of the rod = 4.2 rad/s

Kinetic energy of the rod is:

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.