The acceleration of free fall on a certain planet is 8.0 m s-2. An object gets dropped from a height and hits the ground after 1.5 s. From what height must the object have been dropped?

We are given that:

We need to find:

Using equations of motion:

➙ v² - u² = 2as

➙ v = u + at

here,

From the given information, we can conclude that:

Now, using equation of motion:

➝ v = u + at

➝ v = 0 + ( 8 × 1.5 )

➝ v = 0 + 12 .0

➝ v = 12 m/s

For, acceleration :

➝ v² - u² = 2as

➝ ( 12 )² - ( 0 )² = 2 × 8 × s

➝ 144 - 0 = 16s

➝ 16 s = 144

➝ s = 144 / 16

➝ s = 9m

Since, we take displacement in terms of distance in some places, therefore we can say that the height from which the object was dropped is 9 meters .

c. rb

explanation:

the atomic radius of a chemical element is a measure of the size of its atoms, usually the mean or typical distance from the center of the nucleus to the boundary of the surrounding shells of electrons.