3 kg of water (c = 4,186 J /kg°C) is at an initial temperature of 10°C. If 7,700 J of heat is applied, what will be its final temperature? Show all of your work and use the correct units for full credit.

Given :-Here , The initial temperature of 3kg of water is 10° CThe heat supplied to 3kg water is 7,700 JThe specific heat of water is 4186 J/kg ° C To Find :-We have to find the final temperature of water .Let's Begin :-

Here, we have

Mass = 3 kg Specific heat capacity = 4186 J/kg°CInitial temperature = 10° CHeat applied = 7,700J

We know that,

Specific heat is the heat that is required to increase the temperature of 1 kg or unit mass by 1° C or unit ° C

That is,

Here, Change in temperature is ΔT that is, Final temperature - Initial temperature

So,

Subsitute the required values,

Hence, The final temperature of 3kg if 7,700 J of heat supplied is 10.61 °C