Physics, 18.02.2022 14:10 jmdlightsout12345

A car travels with a velocity of 18km/hr, then it accelerates uniformly and travels a distance of 5m. If the velocity reached is 54 km/hr, find the acceleration and the time taken to travel this distance.

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Answer from: nataoli3375

Explanation: Vi = 18k/hr = 18 x 1000/3600 = 5/s

Vf = 54k/hr = 54 x 1000/3600 = 15/s

S = 5

a = ?

t = ?

BY USING NEWTON 3RD EQUATION OF MOTION

2aS= Vf^2-Vi^2

a = Vf^2 - Vi^2/2S

a = 15^2 - 5^2/2(5)

a = 20

BY USING NEWTON 1st EQUATION OF MOTION

Vf = Vi + at

t = Vf-Vi/a

t = 15-5/20

t = 10/20 = 1/2 sec = 0.5 sec

Answer from: Dvrsug8598

The acceleration of the car is 20 m/s²

What is acceleration?

This is the rate of change of velocity. To calculate the acceleration of the car, we use the formula below.

Formula:

v² = u²+2as Equation 1

Where:

v = final velocityu = initial velocitya = acceleration of the cars = distance traveled .

Make a the subject of the equation

a = (v²-u²)/2s Equation 2

From the question,

Given:

u = 18 km/h = (18×1000/3600) = 5 m/sv = 54 km/h = (54×1000/3600) = 15 m/ss = 5 m

Substitute these values above into equation 2

a = (15²-5²)/(2×5)a = (225-25)/10a = 200/10a = 20 m/s²

Hence, The acceleration of the car is 20 m/s².

Learn more about acceleration here:

Answer from: Quest

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Answer from: Quest

Full change in the electric plus system

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A car travels with a velocity of 18km/hr, then it accelerates uniformly and travels a distance of 5m...