a car is traveling at 10 m/s accelerates 2 m/s^2 until is traveling at 20 m/s How much time did it take to reach the final velocity

   5sec

Explanation: BY USING FIRST LAW OF NEWTON MOTION

                       Vf = Vi + at

                        t  = Vf - Vi/a

                         t =  20 - 10/2

                          t =   5sec

im guessing the west of station b

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s