A ball of mass 1.84 kg is dropped from a height y, = 1.49 m and then bounces back up to a height of y, = 0.87 m.
How much mechanical energy is lost in the bounce?

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11.408 joules

Explanation:

soln

From the question above

Mass of ball = m = 1.84kg

Height of ball when dropped = 1.49m

Height of ball when it bounces back up = 0.87m

Recall

Potential energy (P.E) = mass × height × g

Kinetic energy(K.E) = 1/2 × mass × (velocity)²

Mechanical energy = K.E + P.E

M.E lost = M.E when ball dropped – M.E when ball bounces back up

Recall that g = acceleration due to gravity = 10ms²

P.E/K.E when ball dropped = 1.84 × 1.49 × 10

P.E/K.E when ball dropped = 27.416J

P.E/K.E when ball bounces back = 1.84 × 0.87 × 10

P.E /K.Ewhen ball bounces back = 16.008J

Since P.E = K.E

M.E when ball dropped = 27.416J

M.E when ball bounces back = 16.008J

Therefore,

M.E lost = 27.416 - 16.008

M.E lost = 11.408Joules

kepler used the data from tycho blahe (his mentor) to construct the laws of planetary motion.

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.