A proton and an alpha particle are momentarily at rest at a distance y from each other. They then
begin to move apart. Find the speed of the proton
by the time the distance between the proton and
the alpha particle doubles.
Both particles are positively charged. The charge
and the mass of the proton are, respectively, e and
m. The charge and the mass of the alpha particle
are, respectively, 2e and 4m.
Find the speed of the proton (Ur )p by the time the distance between the particles doubles. Express your answer in terms of some or all of the quantities e, m, r, and ε.

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day

its a 5.5 n

glad that