A box of mass 3.6 kg is lifted 5.4 m above the ground. What is the change in energy in lifting
the box to this height?

So, the energy change that occurs is 190.512 J.

Introduction

Hello ! I am Deva from Indonesia will help you regarding energy and its transformation. In this case, it's the use of energy from the lifter to be equivalent to the change in the object's potential energy. Why potential energy? Because the box undergoes a change in height and the potential energy specializes at a certain height. Work (W) due to change in potential energy () can be realized in the equation :

With the following condition :

W = work of subject (J) = change of potential energy (J)m = mass (kg)g = acceleration of the gravity (m/s²) = final height (m) = initial height (m)Problem Solving

We know that :

m = mass = 3.6 kgg = acceleration of the gravity = 9.8 m/s² = final height = 5.4 m = initial height = 0 m

What was asked :

W = work of subject = ... J

Step by step :

So, the energy change that occurs is 190.512 J.

When seismic waves hit a fault, the waves are reflected off the fault. seismograph can detect these reflected seismic waves. geologists then use these data to map the fault's length and depth

Answerthe force between the charges will be  f/9 (one-ninth of force f)explanationcoulomb's law relates the magnitudes  two point charges q₁ and q₂, the distance, r, between the charges, and the electrostatic force, f, between the two charges:     k represents coulomb's constant, k = 8.99×10⁹ n·m²/c².note that if we have r = 3r, then