An 8cm tall object is 15cm away from a lens and produces a real image that is twice the size of the object.
A. Use the lens equation to calculate the focal length of the lens
B. If the same object were in the same position in front of a lens that had the same focal length as the one above, but was a diverging lens, how tall would the image be?
C. Now assume that the object is 6.0cm in front of the original converging lens. How tall will the resulting image be?
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