and a head-on collision a 2,250 kg car moving North with the speed of 22 m/s strikes to 3,800 km truck moving south at a unknown speed after the collision both vehicles bounce back in the opposite direction from which they were originally moving if the car bounces South with a speed of 28 m/s and the truck bounces North with the speed of 8 m/s how fast must the truck have been moving before the collision

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

distance = 150m

displ = root (50 ^2 + 100^2)

root(2500+10000)

root 125000