Speakers C and D emit the same pure tone of wavelength 1.5 m, are exactly in phase, and are 3.6 m apart. An observer begins at point P, equidistant to the two speakers, and moves directly to point Q along the path shown. Point Q is the position of the 1st loud spot (completely constructive interference) encountered after leaving point P. Point Q is _ m further from D than from C. Please help. The answer is 1.5 but I don't know how to get there because my teacher never did an example like this.

the area between the graph and the t axis

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle  

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.