A box, initially at rest, has 36.7 N of force exerted on it for 2.81 s. If the box has a mass of 7.41 kg, what was its velocity at this time?

Hi there!

We can begin by calculating the acceleration of the box using Newton's Second Law:

∑F = Net force (N)

m = mass (kg)

a = acceleration (m/s²)

Rearrange to solve for acceleration:

Now, we can use the kinematic equation:

vf = Final velocity (? m/s)

v0 = initial velocity (0 m/s, from rest)

a = acceleration (m/s²)

t = time (s)

Plug in the values:

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever