In the system drawn on the right, m_1 = 2.0 kg sits on a lab table which is 110 cm tall. m_2 = 1.0 kg is hanging over a pulley and is initially at rest 60.0 cm above the floor. The system is released. Determine the speed of m_2 just before it hits the floor. (solve with work-energy ideas, considering the system) a) solve the problem assuming the table is frictionless.
b) coefficient of friction is .2 between m1 and the table

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards

the correct answer is "inertia"