A proton of mass 1.67 x 10-27 kg (the charge of a proton is 1.6 x 10-19 C) enters the region between two parallel plates a distance 28.0 cm apart. There is a uniform electric field of 3.00 x 10 V/m between the plates. If the initial speed of the
proton is 5.00 x 10m/s what is it's final speed?

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

You yeah with the side of the yeah with a little bit of yeah.

The disturbance in a transverse wave is perpendicular to the wave motion.unlike a transverse wave, the disturbance in a longitudinal wave is parallel to the wave motion (a), that is, back and forth.