The mass of a newborn baby is 3.5 kg. Which solution solves for the force of the Earth on the baby? Fe = gem N -9.8 (3.5 kg) FE = (-9 M( ) = Fe = -34.3N Fe = gem N 3.5 kg = () -9.8 m kg m m 3.5 kg 9.8 N/kg 0.36 kg Fe = gem -9.8 N = g(3.5kg) -9.8 N 9(3.5kg) 3.5 kg 3.5 kg g= -2.8 N/kg FE = GEM N -9.8 (3.5kg) kg FE 34.3 N F:- () 1

What’s #16 asking and how do i solve it?

An charge with mass m and charge q is emitted from the origin, (x, y)=(0,0). a large, flat screen is located at x=l. there is a target on the screen at y position y(h), where y(h) > 0. in this problem, you will examine two different ways that the charge might hit the target. ignore gravity in this problem. 1.assume that the charge is emitted with velocity v(0) in the positive x direction. between the origin and the screen, the charge travels through a constant electric field pointing in the positive y direction. what should the magnitude e of the electric field be if the charge is to hit the target on the screen? express your answer in terms of m, q, y(h), v(0), and l. 2.now assume that the charge is emitted with velocity v(0) in the positive y direction. between the origin and the screen, the charge travels through a constant electric field pointing in the positive x direction. what should the magnitude e of the electric field be if the charge is to hit the target on the screen? express your answer in terms of m, q, y(h), v(0), and l.

An owl dives toward the ground with a constant velocity of 4.40 m/s at 53.0° below the horizontal. the sun is directly overhead and casts a shadow of the owl directly below it. what is the speed (in m/s) of its shadow on level ground?