Physics, 03.12.2021 07:50 lchynnawalkerstudent
Gap region between the diver's skin and her
wetsuit, forming a water layer about 0.5 mm thick.
Assume that the total surface area of the wetsuit
covering the diver is about 1.0 mº, and that the
water enters the suit at 10 °C and is warmed by
the diver to skin temperature of 35°C. The specific
heat of water is 1.00 kcal/kg - Cº.
Estimate how much energy (in
units of candy bars = 300 kcal)
is required by this heating
process.
Express your answer using
two significant figures.
Answers: 1
Physics, 22.06.2019 07:20, hardwick744
If 2 moles of co_2 at 2l and 500k are expanded reversibly to 20l, more work can be obtained from an adiabatic process than from an isothermal process. is the above statement true or false?
Answers: 3
Physics, 22.06.2019 19:10, simmonss1185
3. a worker pushes a 30.5 kg polished stone along a polished table with a force on bonin a straight line for 5.20 s after starting from rest. there is no friction between thestone and the table. at the end of the table. the stone is hooked to a cable with a lengthof 62.0 cm to rotate it to a rough table to store until they can be picked up. the roughtable has a coefficient of static friction 0.702 with the polished stone. remember that 8= 9.80 m/s2a) what is the speed of the stone when it is hooked to the cable? b) what is the tension in the cable while the stone is rotating? (there is still nofriction)c) how much force is needed to make the stone begin sliding from rest on therough table? ius = 0.70262.0 cm30.5 kg20.5 kg6= 0
Answers: 2
Physics, 22.06.2019 22:10, bankrollbaby01
M1 = 2.8 kg, m2 = 6.72 kg, m3 = 11.2 kg, byas in .is ,is .toof m3 it 0.91 m. (in m/s)
Answers: 3
Gap region between the diver's skin and her
wetsuit, forming a water layer about 0.5 mm thick.
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