A toroid having a square cross section, 0.43 cm long on a side, with a 0.51 cm inner radius has 298.00 turns and carries a current of 2.30 A. It is made of a square solenoid bent into a donut shape. What is the magnetic field inside the toroid at the outer radius

this is a good question! i'll do some research and come back when i have the answer!

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft