A 32kg box is pulled at a constant speed along a horizontal surface by a rope with tension FT. The rope is inclined at an angle from the horizontal as shown. The block moves a distance 11m along the horizontal surface. What is the net work done by all the forces acting on the block? The acceleration of gravity is 9.8 m/s^2

Cis the

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

120v is the answer i am positive tell me if this was correct