A truck has a mass of 1,850 kg. The engine of the truck applies a force of 9,600 N to the truck toward the south. The
friction between the wheels and the road acts in the
opposite direction. The friction has a magnitude of 8,200 N.
What is the magnitude of the truck's acceleration?

Did you ever figue this

Bag of bolts weight 29.4n

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.