A body starting from rest accelerates uniformly at the rate of 5m/s² for 6 seconds. it travels at the speed attained for a time t seconds before coming to rest in 20 seconds. if the body covers a total distance of 2 km. (I) sketch the velocity time graph for the motion of the body (II) calculate the time t

Ibelieve the answer is b

Initial velocity,  u = 4.9 m/sfinal velocity = v m/sinitial height,  h₁ =  245 m    final height, h₂ = 0a = -9.8  m/s²time taken = t secondss = ut + 0.5at²⇒  (h₂-h₁) = ut + 0.5at²⇒  0-245 = 4.9t + 0.5×(-9.8)×t²⇒ -245 = 4.9t - 4.9t²⇒ 4.9t² -4.9t -245 =0solving it, we get   t = 7.59sv  = u +  at = 4.9 -9.8×7.59 = 4.9 - 74.38 = -69.48 m/svelocity is  69.48 m/s downward

So are u adding some additional catalyst

Im not from america so could you explain what route 70 is? how much km or miles does it have? am i supposed to know ,from this text,what the s(road) is? how many km or miles it has?