A voltmeter is accurate to 98% of its full scale reading. (i) If a voltmeter reads 200V on 500V range, what is the absolute error?
(ii) What is the percentage error reading of Part (i)?

200 =/-5%.

Explanation:

This method of specifying accuracy seems odd to me. Since it is unclear I will assume that you really mean +/-2% of full scale. I will also assume that you are speaking of an analog meter because digital meters require a percentage and a count to specify accuracy. This makes that real accuracy a bit more complicated.

You are using a 500 volt range. At +/-2% this means +/- 10 volts. If your scale reading is 200 volts you may assume that the “real” value is between 190 volts and 210 volts. If you want to express the error in terms of the reading it would be 200 =/-5%.

Accuracy is expressed in different ways for convenience and marketing reasons. Here is a table to convert the various ways accuracy is expressed.

i think it’s a. this is because if they measured the mass of something with a mass of 150g, then their final answer would have to be approximately 150g. though all of their answers are almost 150, rosa and tran have the closest answers (or the exact answer) to the accurate one.