At the National Zoo, a gorilla pushes a 14.4 kg tire across the frictionless floor of his habitat with a force of 79.2 N. What is the acceleration of the tire?

explanation:

the masses of the objects and the distance between them

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft