Two boxes, m2 = 10 kg and m1 =15 kg, are attached to each other by a lightweight string and are pulled by another string attached to m1 . If the string pulling the box in the front has a force
of 500 N. what is the acceleration of m1 assuming the strings are kept taut? Neglect resistance
forces.
50 m/s/s
33.3 m/s/s
20 m/s/s
10 m/s/s

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

think its the third option

distance = 150m

displ = root (50 ^2 + 100^2)

root(2500+10000)

root 125000