a summer speeds up from 1.1m/s to 1.3m/s during the last 20 s of the workout. what is the acceleration during this interval?

0.01 m/s^2

Explanation:
Given initial velocity = 1.1 m/s, final velocity = 1.3 m/s and time = 20s, we can determine the acceleration using one of the UARM (uniformly accelerated rectilinear motion) formulas:

v final = (acceleration x time) + v initial

Replacing the values gives us:

1.3 = (a)(20) + 1.1

0.2 = 20a

a = 0.2/20

a = 0.01 m/s^2

Hope this helps, brainliest would be appreciated :)