Pls help me with this question its due tomorrow and I can't find the A person jumped 50cm, the hang time for the jump was 0.778 seconds, calculate a value for the acceleration due to gravity. What is the percent error in the value for acceleration you found? (Solve it without factoring in the air)

S = ut + 1/2gt²

where S = distance

50 cm = 0.5m

u is initial velocity = 0

S = 0*t + 1/2gt²

S = 1/2gt²

0.5 = 1/2 g (0.778²)

2*0.5 = g(0.778²)

1/(0.778²) = g

g = 1.65m/s²

The value of g is grossly errored due to the values obtained since the known value of g on earth is 9.8m/s² the obtained value rounds off to the value of g on moon.

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .