What is the pressure at the bottom of a tank 1 m deep? Take the density of water to be 1000 kg/m^3, and gravitational acceleration to be 9.8 m/s^2. Enter your answer in N/m^2. What would the pressure at the bottom of the tank in the previous question be if it were in an elevator accelerating upward at 2 m/s^2?

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Answer: 1.4 seconds which is the third optionexplanation: current is defined as the flow of charge per timetherefore, the equation that relates current, charge and time can be expressed as follows: i = δq / δtwhere: i is the current given = 1.8 ampereδq is the charge given = 2.5 coulombδt is the time required for the flow of the given charges to give the 1.8 ampere.substitute with the givens in the above equation to get the time as follows: 1.8 = 2.5 / δtδt = 2.5 / 1.8 = 1.38888 which is approximately 1.4 secondshope this was !