HELP ASAPP!!! 4.) If you change the 2 in front of 2O2 to a 3, what will be the change in the results on the right side of the equation?
A.) There are now 3CO2 molecules
B.) Nothing changes in the equation
C.) There is an extra O2 molecule left over
D.) There are now 3H2O molecules

5.) Which procedure could be used to demonstrate that matter is conversed during a physical change?
A.) Find the mass of a cup of water. Boil the water. Find the mass of the water that remains.
B.)Find the mass of a raw egg. Cook the egg. Find the mass of the cooked egg.
C.) Find the mass of a piece of ice. Let the ice melt. Find the mass of the liquid water.
D.) Find the mass of an apple. Cut the apple and remove the core. Find the mass of the remaining apple.

6.) One molecule of bromine (Br2) and two molecules of potassium chloride (KCI) combine in a reaction. How many atoms are in the products?
A.) three
B.) six
C.) four
D.) two

Kinetic energy = 1/2mv^2. since the mass is constant we can form a ratio of it's kinetic energy at 60 divided by that at 30 to see ke(60)/ke(30) = +(60^2)/30^2). this may be said to 300% increase.

Are a.larger

Answer: a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same sign as the  -4.0  µc charge.======electricstatic force between two point charges  is given by    where k is coulomb's constant,  8.99×10⁹  n·m²/c², q₁ and q₂ are the point charges, and r is the distance between the two point charges.assign positive to q₁let q₁ =  6.0 µc, q₂ = -4.0  µc, q₀ represent the charge at the origin, and q₃ represent this new charge to place.the charge at the origin q₀ would experience the following force f₀₁ from q₁, with r = 6.0 m (note that 1  µc = 10⁻⁶ c)    the force from q₂    the force from q₃    the net force on the origin charge, q₀, has to be zero for no electrostatic forcehaving an equation where k and q₀ can be divided out of the equation will allow us to solve for q₃    isolating:     a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same as the  -4.0  µc charge