Two point charges qı = 2.20 nC and q2 = -6.40 nC are 0.100 m apart. Point A is midway between them; point B is 0.0800 m
from qı and 0.0600 m from 22 (Figure 1). Take the electric
potential to be zero at infinity.
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Part A) express your answer in volts

Part B) Find the potential at point B express answer in volts

Part C) find the work done by the electric field on a charge of 2.70 nC that travels from point B to point A, express answer in joules

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explanation:

there are no correct statementd on the list of choices you provided.

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

-reverse card

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards