Vector A is added to a second vector B which has an x-component of 3 m and a y- component of -5 m. The resultant (A + B) is in the negative x direction and has a magnitude of 4 m. Find the magnitude and direction of A.

Explanation:

As B has a y component of -5, A must have a y component of 5 to have the result lie on the x axis.

As B has an x component of 3 and the result has an x component of -4, A must have an x component of -7

A = (-7, 5)

magnitude A = √(7² + 5²) = √74  ≈ 8.60

θ = arctan(y/x) = arctan(5/-7) ≈ 144.46° CCW from the positive x axis

since you're a real machine, your ama is always less than your ima, because you can never totally eliminate friction.

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14