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Physics, 09.09.2021 03:30 lenniestreet10

The Rydberg equation for the hydrogen atom is given by (1/λ) = RH (1/nf^2 - 1/ni^2)
Where RH is the hydrogenic Rydberg constant, 1.0974×10^7m^−1, nf and ni are the final and initial principal quantum numbers of the energy levels, respectively. (The transition is from ni to nf )
The Balmer series are emission lines associated with transitions ending at the n = 2 principal level.
What is the upper principal level that generates a transition at 656.3 nm?
(1nm=10^−9m)


The Rydberg equation for the hydrogen atom is given by

(1/λ) = RH (1/nf^2 - 1/ni^2)
Where RH is t

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The Rydberg equation for the hydrogen atom is given by (1/λ) = RH (1/nf^2 - 1/ni^2)
Where RH...

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