an object 5cm in size is placed at 25cm in front of a concave mirror of a focal length 15cm. at what distance from a mirror should a screen be placed inorder to obtain a sharp image?find the nature of size of the image?​

6/12=1/2

step-by-step explanation:

overcharge is the right answer system

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j