A constant net force is applied to an object. Suddenly, the object's mass doubles, but the net force remains the same. For this to happenthe acceleration must do what? A:Quadruple
B:Double
C:Stay the same
D:Halve

D: Half

We know that,

F = m.a, where F is the force, m is the object's mass and a is the acceleration.

In the first case, we observed that a1 = F/m.

In the second case, we observed that the mass has been doubled, so a2 = F/2m .

By the ratio of the two cases, we get

a1/a2 = F/m / F/2m

or, a1/a2 = 2

or, a1 = 2.a2

or, a1/2 = a2

Therefore, the acceleration gets half of it's original measurement.

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .