subject
Physics, 06.09.2021 18:30 brittanydeanlen

The position vector of the point (−4,−2,1) P ( − 4 , − 2 , 1 ) with respect to (−4,−5,−1) R ( − 4 , − 5 , − 1 ) is

ansver
Answers: 2

Other questions on the subject: Physics

image
Physics, 21.06.2019 23:30, 20calzoy
The most important difference between a wedge and an inclined plane is a. their size b. their shape c. how they are used d. what they are made of
Answers: 1
image
Physics, 22.06.2019 01:00, winnie45
Red’s momentum vector before the collision is green’s momentum vector after the collision. question 1 options: shorter than longer than equal to question 2 (1 point) saved since green bounces off red, this must be an collision. question 2 options: explosion inelastic elastic question 3 (1 point) saved red transfers of its momentum to green during the collision. question 3 options: little all most none question 4 (4 points) why does red transfer all its momentum to green? back up your answer with information from the simulation. write at least 2 sentences. question 4 options: skip toolbars for . more insert actions. more text actions. more paragraph style actions. question 5 (1 point) now make red much heavier than green. answer the questions below to describe how both red and green behave after the collision. you might want to play the sim multiple times. click on restart or return balls to start over. to see numbers, check the show values box (inside the green box). red during the collision because it transferred some momentum to green. question 5 options: sped up kept the same velocity slowed down question 6 (1 point) green sped up during the collision as it question 6 options: lost momentum to red maintained a constant momentum. gained momentum from red question 7 (1 point) after the collision . . question 7 options: red bounced off green and went to the left. green moved to the right. both green and red stopped as they have lost all momentum. red stopped and green moved to the right. both green and red moved to the right. question 8 (4 points) only some of red’s momentum was transferred to green. why did this occur? back up your answer with information from the simulation. write at least 2 sentences. question 8 options: skip toolbars for . more insert actions. more text actions. more paragraph style actions. question 9 (1 point) now make red much lighter than green. answer the questions below to describe how both red and green behave after the collision. you might want to play the sim multiple times. click on restart or return balls to start over. to see numbers, check the show values box (inside the green box). which is true about the collision? question 9 options: green slowed down after the collision therefore it must have lost momentum. green sped up after the collision therefore it must have lost momentum. green sped up after the collision therefore it must have gained momentum. green slowed down after the collision therefore it must have gained momentum. question 10 (1 point) since green gained momentum, red had to have momentum because you cannot create or destroy momentum. question 10 options: lost kept the same amount of gained question 11 (1 point) since green was so much and harder to move, it caused red to bounce back to the left giving red . question 11 options: lighter. . . . negative heavier . . . . negative lighter. . . . positive heavier . . . . positive question 12 (4 points) now, click on more data at the bottom of the sim. play with different numbers for the masses and starting velocities. you can even make the starting velocities negative! tell me one thing you discovered by adjusting the speeds and masses. write at least 2 sentences. be specific and use words like velocity, momentum, mass, increased, decreased, etc. question 12 options: skip toolbars for . more insert actions. more text actions. more paragraph style actions. part 2: inelastic collisions question 13 (1 point) click on the "less data" box at the bottom of the sim. in the green box, slide the elasticity meter all the way to inelastic so there is 0% elasticity: make the masses whatever size suits you. make sure that green starts out with a velocity of 0 m/s – if you didn’t change this in the last step, you don’t need to do anything. push play and observe! true or false: when red and green collide, they stick together. question 13 options: true false question 14 (1 point) the velocity of red & green after the collision is the velocity that red started off with. question 14 options: larger than smaller than equal to
Answers: 1
image
Physics, 22.06.2019 02:50, lilybear1700
Steam is generated in a boiler of a cogeneration plant at 10 mpa and 450°c at a steady rate of 5 kg/s. in normal operation, steam expands in a turbine to a pressure of 0.5 mpa and is then routed to the process heater, where it supplies the process heat. steam leaves the process heater as a saturated liquid and is pumped to the boiler pressure. in this mode, no steam passes through a condenser, which operates at 20 kpa. (a) determine the power produced in the turbine and the rate at which process heat is supplied in this mode. (b) determine the power produced in the turbine and the rate of process heat supplied if only 60 percent of the steam is routed to the process heater and the remainder is expanded to the condenser pressure. (3.32 mw; 9.69 mw; 4.25 mw; 5.82 mw)
Answers: 3
image
Physics, 22.06.2019 07:10, cannan
Search coils and credit cards. one practical way to measure magnetic field strength uses a small, closely wound coil called a search coil. the coil is initially held with its plane perpendicular to a magnetic field. the coil is then either quickly rotated a quarter-turn about a diameter or quickly pulled out of the field. (a) derive the equation relating the total charge q that flows through a search coil to the magnetic-field magnitude b. the search coil has n turns, each with area a, and the flux through the coil is decreased from its initial maximum value to zero in a time ∆t. the resistance of the coil is r, and the total charge is q = i∆t, where i is the average current induced by the change in flux. (b) in a credit card reader, the magnetic strip on the back of a credit card is rapidly “swiped” past a coil within the reader. explain, using the same ideas that underlie the operation of a search coil, how the reader can decode the information stored in the pattern of magnetization on the strip. (c) is it necessary that the credit card be “swiped” through the reader at exactly the right speed? why or why not?
Answers: 2
You know the right answer?
The position vector of the point (−4,−2,1) P ( − 4 , − 2 , 1 ) with respect to (−4,−5,−1) R ( − 4 ,...

Questions in other subjects: