. A projectile is launched from a cliff 100m above level ground with a velocity of 30m/s at an angle 20⁰ above the horizontal. Determine the projectile’s a) Range, b) pick height, c) velocity at
2s after launch.

How to find the maximum height of a projectile?

if α = 90°, then the formula simplifies to: hmax = h + V₀² / (2 * g) and the time of flight is the longest. ...

if α = 45°, then the equation may be written as: ...

if α = 0°, then vertical velocity is equal to 0 (Vy = 0), and that's the case of horizontal projectile motion.

ammonium chloride & tallow

false.

explanation:

this statement is false. after falling for 5 seconds, its speed will not be 100 m/s.