1. A charge of 1,67 C flows through the filament of a particular light bulb in 2,00 s. 1a) Calculate the current flowing through the light bulb. (b) Calculate the number of electrons that pass through the filament every second. 2. A current of 5 A flows through a wire for 4,0 minutes. How much charge passes through any given cross-section of the wire?​

Explanation:

Correct option is

A

10

20

Given : I=1A,t=16s,e=1.6×10

−19

C

Step 1: Current drawn by the filament

I=

t

Q

=

t

Ne

(Since Q=Ne, where N is the number of electrons crossing in time t)

⇒N=

e

I t

(1)

Step 2: Substituting the values in equation (1)

N=

e

I t

=

1.6×10

−19

C

1A×16s

=10

20

Hence, number of electrons passing through a cross section of the filament in 16 seconds would be 10

20

.

amplitude

hope this