13. In a Millikan's oil drop experiment a drop is observed to fall with a terminal speed 1.4mm/s in the absence of electric field. When a vertical electric field of 4.9x10v/m is applied the droplet is observed to continue to move downward at lower terminal speed 1. 71 mm/s. calculate the charge on the drop (Density of oil = 750kg/m3, viscosity of air=1.81 x 10^-5 kg/ms ,density of air=1.29 kg/m3) ​

most of them using statistics and defining how things are being measured

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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you go to your settings preference and in the end youll see sth that says "i want to delete my acc" click on it and u'll acc will be deleted but u have to wait.