Part C Now observe the graph of the vertical velocity against time (vy vs. t). To do so, click the "Y"label on the vertical axis and select "vy: velocity y-
component" from the pop-up menu.

Because the dept in the ocean

If the heat engine is a perfect carnot cycle engine, thenefficiency = (t2-t1)/t2   where t1=temperature of cold reservoir ( ° k) = 135            t2=temperature of hot reservoir ( ° k)   = 325thereforeefficiency = (t2-t1)/t2 = (325-135)/325 = 0.5846 = 58%  note: this is the theoretical maximum efficiency of a perfect heat engine.   real-life engines do not achieve this value.

Idk just need points

Answerit increases at a steady rate;