An electric motor has an effective resistance of 29.4 Ω and an inductive reactance of 42.6 Ω when working under load. The rms voltage across the alternating source is 442 V. Calculate the rms current.

connect the batteries in series and hope

0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr

1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j