g A light bulb operating at a dc voltage of 120 V has a power rating of 60 W. How much current will flowthrough this bulbif it is connected to a 60-V dc power supply

the current is 0.6

voltage ÷ resistance = current

so 12 ÷ 20 = 0.6

96.77 amp

explanation:

rl = 250/100 = 2.5 ohms.

egl = 250 + (100 × 0.1) + 2 = 262 v.

at 700 r.p.m., eg2 = 262 × 700/1000 = 183.4 v.

if ia is the new current, then eg2 - 2 - (ia × 0.1) = 2.5 ia

which means this will give ia = 96.77 amp.