A circular saw blade of diameter 0.210 m starts from rest. In a time interval of 6.40 s it accelerates with constant angular acceleration to an angular velocity of 132 rad/s with constant angular acceleration. Find the angular acceleration and the angle through which the blade has turned in this time. So, I used α=Δω/Δt = (140 rad/s)/(6.00s) = 23rad/s
Is this answer right?
Also, to find θ, which equation do I use??? Do I use Δθ=ω0t+1/2αt2 or can I simply use Δθ=ωΔt as derived from the equation ω=Δθ/Δt?

Which of the following is true about an object in free fall? its acceleration depends on its mass. it has no inertia. it pulls on earth, and earth pulls on it. its momentum is constant.

What is the type of the reaction below? bacl2 + h2so4 → 2 hci + baso4 double replacement synthesis single replacement decomposition

A3030 cmcm wrench is used to loosen a bolt with a force applied 0.30.3 mm from the bolt. it takes 6060 nn to loosen the bolt when the force is applied perpendicular to the wrench. how much force would it take if the force was applied at a 3030 degree angle from perpendicular? a 3030 cmcm wrench is used to loosen a bolt with a force applied 0.30.3 mm from the bolt. it takes 6060 nn to loosen the bolt when the force is applied perpendicular to the wrench. how much force would it take if the force was applied at a 3030 degree angle from perpendicular?