Mahiya and Mrinmoy are in a relay around a square field with each side of length 60m. First, Mahiya runs at a speed of 6 ms−1 for 60m to pass a baton to Mrinmoy. Then Mrinmoy runs 120m at 4ms−1 while Mahiya runs through the field to reach the other corner. Then Mrinmoy passes the baton. But Mahiya is now tired since she has been constantly running. So, she only runs at 3ms−1 for the final 60m. What is the average speed of the baton in ms−1?

The average speed of the baton can be determined by dividing the total distance travelled by the total time taken for that travelling.

First, we will find the total distance, by adding the distances travelled by both Mahiya and Mrinmoy, while carrying the baton.

Total Distance = 60 m + 120 m + 60 m = 240 m

Now, we will find the total time taken for this travelling. To find out the total time we will divide each distance travelled by the speed of the traveller during that distance:

Total Time = 60 s

Now, we finally find the average speed of the baton by using the formula:

Average Speed = 4 ms⁻¹

Learn more about average speed here:

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.

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