Your physics TA has a far point of 0.759 m from her eyes and is able to see distant objects in focus when wearing glasses with a refractive power of −1.35 D. Determine the distance between her glasses and eyes.

Explanation:

From the question we are told that:

Far point

Refractive power

Generally, the equation for Focal length is mathematically given by

Therefore

Where

Therefore,The between her glasses and eyes

see earlier

you'd use the equation that establishes a relationship between  energy  and  wavelength, which looks like this

e=h⋅cλ, where

λ  - the wavelength of the photon; c  - the speed of light, usually given as  3⋅108m/s; h  -  planck's constant, equal to  6.626⋅10−34j s

plug the value you were given for the energy of the photon in the above equation to get the wavelength

e=h⋅cλ⇒λ=h⋅ce

λ=6.626⋅10−34js⋅3⋅108ms−1.257⋅10−24j=1.581⋅10−1m