A plane flying at an altitude of 33,000 feet at a speed of 630 miles per hour releases a bomb. Find the tangential and normal components of acceleration acting on the bomb.

Ignoring air resistance . . .

After the bomb is released, tangential (horizontal) acceleration is zero,, normal (vertical) acceleration is 9.8 m/s^2 down (gravity).

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s